Write a c program to store records of n students based on roll_no, name, gender and 5 subject marks i) Calculate percentage each student using 5 subjects. ii) Display the student list according to their percentages

 

#include<stdio.h> #include<string.h> #include<stdlib.h> struct student { int roll_no; char name[50]; char gender; int marks[5]; float percentage; }; int main() { int n; printf("enter the number of students "); scanf("%d",&n); struct student s[50]; for(int i=0;i<n;i++) { printf("enter roll no. "); scanf("%d",&s[i].roll_no); printf("enter name. "); scanf("%s",&s[i].name); printf("enter gender "); scanf("%s",&s[i].gender); printf("marks of five subject"); for(int j=0;j<5;j++) { scanf("%d",&s[i].marks[j]); } int total=0; for(int j=0;j<5;j++) { total = total+s[i].marks[j]; } s[i].percentage = total / 5; } for (int i = 0; i < n - 1; ++i) { for (int j = 0; j < n - i - 1; ++j) { if (s[j].percentage < s[j + 1].percentage) { struct student temp = s[j]; s[j] = s[j + 1]; s[j + 1] = temp; } } } printf("\nStudent List sorted by Percentage:\n"); printf("Roll No\tName\tGender\tPercentage\n"); for (int i = 0; i < n; ++i) { printf("%d\t%s\t%c\t%.2f\n", s[i].roll_no, s[i].name, s[i].gender, s[i].percentage); } }